Construction Of Welding Machine

NUMBER OF LAMINATION
Et = 4.44f ϴ MA …………..(i) [Faraday’s low of transformation(Joseph Henry (2006]
A = Et = 0.99 x 104
    4.44 x 50 x 1.54 = 28.96cm2
    Since A and L2       
Where A is the cross – sectional area of lamination L is the length
A = CL2 where C is the constant of proportionality, C is given to be 0.45
L2 = A……………………………(ii)b(Joseph Henry 2006)
        C  
L = √A
         C
L = √(█(28.96 @0.45)) = 8cm
Number of lamination = Length of stack
             Thickness of lamination …….. (iii) (Joseph Henry 2006)
                    = (8 x 10)
                          0.5
                    = 160cm (number of lamination)
Total number of lamination = 160 x 2
                            = 320cm
TRANSFORMER EFFICIENCY
    The total losses are the sum of the iron and copper losses obtained by the open circuit and short circuit test.
    Efficiency = output power
                   Input power
Input power = output + Losses ………………………..(i) (Arthur William 1892)
Output power = 1v cos ϴ………………….(ii) (Arthur William(1892)
            = 185 x 200
            = 37000 watts
Efficiency = 8640  x 100
        3700
 = 0.2335 x 100
= 23.4%
(1)    Moss of aluminum conductor = cross sectional area x length of the
     = conductor x destiny of aluminum ……(ii)(Arthur William 1892)
Where A= 3.142 x d 2/4
Where d = 5mm
Therefore A =  3.142 x 52
            4
    = 78. 6  = 19.65mm2
            4
Length of the conductor = 8500km
Density of aluminum = 2800kg /m3
Therefore,
Mass of aluminum of conductor = 19.65 x 8500 x 2800
                    = 467670000kg
(2)    Mass of lamination = Area x thickness x density of steel
    = 8750kg kg/m3……………………….. (iv) (Arthur William 1892)
Where thickness = 1mm
Area of lamination = 300 x 50 = 15000mm2
Mass of lamination = 1500 x 1x 8750 = 131 2500kg
(3)    Mass of container = area x thickness x density of steel x No of sides
Where A = 360 x 360 = 12900mm2
Thickness = 2mm
No of sides = 4
Density of steel = 8750kg/m3
    Mass of container = 129600 x 2 x 8750 x 4
= 9072 000000kg
Total mass = Mass of aluminum + mass of lamination + mass of container
= 467670000 + 13125 + 9072000000
Total mass = 9.35 x 109 kg
Calculation of the quantity of heat generated by lamination during welding using Q = KACAT
    x